?hermite

hermite發(fā)音

英：　　美：

hermite中文意思翻譯

常見釋義：

n.埃爾米特（數(shù)學(xué)家）；厄密；艾米插值

hermite雙語(yǔ)使用場(chǎng)景

1、Propagation of decentered Hermite-Gaussian beams through a misaligned first-order optical system───偏心厄米-高斯光束通過(guò)失調(diào)一階光學(xué)系統(tǒng)的傳輸特性

2、In the new algorithm, a bank of Gauss-Hermite filter (GHF) is used for generating the importance density function.───在濾波算法中，我們用一簇高斯厄米特濾波器(GHF)來(lái)產(chǎn)生重要性概率密度函數(shù)。

3、The propagation properties of elliptical Hermite-Gaussian light beam in a strongly nonlocal nonlinear medium are studied.───研究了橢圓厄米高斯光束在強(qiáng)非局域非線性介質(zhì)中的傳輸特性。

4、A comparative study of propagation properties of Hermite-Gaussian beams through gratings with sinusoidal and rectangular reliefs───厄米-高斯光束通過(guò)正弦和矩形浮雕光柵傳輸特性的比較研究

5、transformation of Hermite Gaussian laser beam through random phase plate is discussed in detail by partial coherence theory in this paper.───本文利用部分相干理論研究了高階厄米-高斯光束通過(guò)隨機(jī)位相片的變換。

6、Numerical simulation of the transformation of Hermite-Gaussian beams through a complicated optical system with multiple hard-edged apertures───厄米-高斯光束通過(guò)多個(gè)硬邊光闌復(fù)雜光學(xué)系統(tǒng)變換的計(jì)算模擬

7、Partially coherent Gaussian beams which can be expanded into an independent superposition of Hermite-Gaussian modes have been analyzed.───分析了以模式間相互獨(dú)立的厄米-高斯光束為基底的部分相干高斯光束。

8、Adopting the Hermite polynomial instead of the Taylor polynomial can greatly decrease the order of high-order cross sensitivity.───采用埃爾米特插值多項(xiàng)式代替泰勒展開式逼近目標(biāo)函數(shù)，極大地降低了高階交叉靈敏度的階數(shù)。

9、Transformation of astigmatic Hermite-Gaussian beams with complex argument by an optical symmetrizing system───對(duì)稱化光學(xué)系統(tǒng)對(duì)像散復(fù)宗量厄米-高斯光束的變換

hermite相似詞語(yǔ)短語(yǔ)

1、baby brother───小弟弟

2、herei am───我有

3、ciphers and codes───密碼和代碼

4、feather boa───n.女用長(zhǎng)圍巾；羽毛披肩；女用長(zhǎng)圍巾

5、emetic herb───催吐草

6、greet her───向她問(wèn)好

7、there is on───這里有

8、there can be───可能有

9、enjoy herself───玩得開心點(diǎn)

10、l like her───我喜歡她

Hermite矩陣是否為對(duì)稱陣

實(shí)對(duì)稱陣一定是Hermite陣

假定Hermite陣A有特征值λ，相應(yīng)的單位特征向量x，那么取一個(gè)以x為第一列的酉陣Q=[x,*]，可得

Q^H * A * Q =

λ 0

0 B

這樣B仍然是Hermite陣，可以對(duì)B用歸納法做酉對(duì)角化